Equations
Time to reach the peak of a vertical launch
Kinematics · id vertical_launch_time
t = \frac{v_0}{g}
| Symbol | Quantity | Unit | Meaning | Usual range |
|---|---|---|---|---|
t | time to peak | s | Time from launch to the highest point | 0 to 100000 |
v0 | launch speed | m/s | Speed straight up at launch | 0 to 1000 |
g | gravitational acceleration | m/s^2 | Local acceleration due to gravity | 1 to 30 |
Assumptions
- Launched straight up
- Air resistance is negligible
- Uniform gravitational field
Valid when
- Speeds far below the speed of light
Found by
Questions with these words retrieve this equation: kinematics, thrown up, straight up, time to peak, how long, top, hang time.
Source
OpenStax University Physics Volume 1, Chapter 3 (reference; entry written by the project). License: MIT. Entry confidence: 0.98.